56c^2+31c+3=0

Solution for 56c^2+31c+3=0 equation:

56c^2+31c+3=0

a = 56; b = 31; c = +3;
Δ = b2-4ac
Δ = 312-4·56·3
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-17}{2*56}=\frac{-48}{112}
=-3/7
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+17}{2*56}=\frac{-14}{112}
=-1/8
$